Calculate the amount of chlorine required to interact with 100 g of iron, which contains 16%

Calculate the amount of chlorine required to interact with 100 g of iron, which contains 16% of impurities that do not react with chlorine.

1.Let’s find the percentage of pure iron:

100% – 16% = 84%.

2.Let’s find the mass of pure iron:

100 g – 100 ;,

x g – 84%,

x = (84 × 100g): 100%,

x = 84 g.

3.Let’s find the amount of iron substance by the formula:

n = m: M, where M is molar mass.

M (Fe) = 56 g / mol.

n = 84 g: 56 g / mol = 1.5 mol.

4. Let’s make the equation of the reaction between iron and chlorine.

2Fe + 3Cl2 = 2FeCl3

2 moles of iron react with 3 moles of chlorine, that is, a quantitative ratio of 3: 2.

Let’s find the amount of chlorine.

2 mol Fe – 3 mol Cl2,

1.5 mol Fe – x mol Cl2,

x mol Cl2 = (1.5 mol × 3 mol): 2 mol = 2.25 mol.

5.Let’s find the volume of chlorine by the formula:

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 2.25 × 22.4 L / mol = 50.4 L.

Answer: V = 50.4 liters.