Calculate the amount of chlorine substance released during the interaction of 24.5 g of berthollet’s salt

Calculate the amount of chlorine substance released during the interaction of 24.5 g of berthollet’s salt with concentrated hydrochloric acid: KClO₃ + HCl = Cl₂ (gas) + KCl + H₂0 select the coefficients using the electronic balance method.

1. Let’s write the equation according to the problem statement:
KClO3 + 6HCl = KCl + 3Cl2 + 3H20 – OBP;
Let’s compose electronic equations:
Cl5 + + 6e = Cl | 1 – oxidizing agent;
2Сl- – 2e = Cl2 | 3 – reducing agent.
Oxygen test: 3 = 3;
The solution was made by the electronic balance method.
2. Calculation:
M (KClO3) = 122.6 g / mol.
3. Determine the number of moles of the starting material:
Y (KClO3) = m / M – 24.5 / 122.6 = 0.2 mol.
4. Proportion:
0.2 mol (KClO3) – X mol (Cl2);
-1 mol                    – 3 mol from here, X mol (Cl2) = 0.2 * 3/1 = 0.6 mol.
Answer: during the reaction, chlorine is released in an amount of 0.6 mol.