Calculate the amount of heat required to evaporate two liters of water taken at the boiling point.
| November 26, 2020 | education
1) We multiply the specific heat of vaporization of water (equal to 2.3 * 10 ^ 6 J / kg) by the mass of water (2L)
2) 2.3 * 10 ^ 6 J / kg x 2kg = 4.6 * 10 ^ 6 J
Answer: 2.3 * 10 ^ 6 J / kg
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