Calculate the amount of heat required to heat 1 cubic meter of gold to 60 ° C.
| November 25, 2020 | education
Tabular data: density p = 19320 kg / m ^ 3, heat capacity c = 128.7 J / kg * K
First, we find the mass of a cube of gold: m = pV = 19320 * 1 = 19320 kg
Heat quantity Q = cm (t2- t1)
Q = 128.7 * 19320 * 60 = 149.19 MJ
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