Calculate the amount of heat required to heat a mixture of 500 g of water and 100 g

Calculate the amount of heat required to heat a mixture of 500 g of water and 100 g of alcohol from a temperature of 20 ° C to a temperature of 60 ° C

Given: m1 (mass of water in the formed mixture) = 500 g (in SI m1 = 0.5 kg); m2 (mass of alcohol) = 100 g (in SI m2 = 0.1 kg); t0 (initial temperature) = 20 ºС; t (final temperature of the mixture) = 60 ºС.

Constants: Cw (specific heat of water) = 4200 J / (kg * K); Cc (specific heat of alcohol) = 2500 J / (kg * K).

The required heat for heating the resulting mixture is determined by the formula: Q = (Cw * m1 + Cc * m2) * (t – t0).

Calculation: Q = (4200 * 0.5 + 2500 * 0.1) * (60 – 20) = 94 * 10 ^ 3 J (94 kJ).