Calculate the amount of heat required to melt 5 kg of lead at a temperature of 327 degrees.
| April 26, 2021 | education
Initial data: m (weight of lead) = 5 kg; t (lead temperature, melting point) = 327 ºС.
Constants: λ (specific heat of fusion of lead) = 25 kJ / kg = 25 * 10 ^ 3 J / kg.
The amount of heat that will be needed to melt 5 kg of lead is calculated by the formula: Q = λ * m.
Let’s perform the calculation: Q = 25 * 10 ^ 3 * 5 = 125 * 10 ^ 3 J or 125 kJ.
Answer: To melt 5 kg of lead, 125 kJ of heat is needed.
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