Calculate the amount of heat required to melt 500 kg of iron taken at a temperature of 39 degrees

Given: m (weight of iron taken) = 500 kg; t0 (initial temperature) = 39 ºС.

Constants: Czh (specific heat of iron) = 460 J / (kg * K); tmelt (temperature of the beginning of melting) = 1539 ºС; λ (specific heat of fusion) = 2.7 * 10 ^ 5 J / kg.

The required heat for smelting 500 kg of iron is determined by the formula: Q = Q1 + Q2 = Czh * m * (tmelt – t0) + λ * m.

Let’s calculate: Q = 460 * 500 * (1539 – 39) + 2.7 * 10 ^ 5 * 500 = 480 * 10 ^ 6 J = 480 MJ.

Answer: To melt 500 kg of iron, 480 MJ of heat is required.