Calculate the amount of heat that is released in the spiral of an 80 ohm tile in 10 minutes. The tile is energized at 120 V.

The given tasks: R (spiral resistance of the taken tile) = 80 Ohm; t (operating time) = 10 min (in SI t = 600 s); U (voltage under which the tile is located) = 120 V.

To calculate the heat released in the spiral of the taken tile, we use the Joule-Lenz law: Q = U ^ 2 * t / R.

Let’s perform the calculation: Q = 120 ^ 2 * 600/80 = 10 ^ 8 * 10 ^ 3 J = 10 ^ 8 kJ.

Answer: In the spiral of the taken tile, 108 kJ of heat will have time to be released in 10 minutes.