Calculate the amount of hydrogen released by the interaction of 30 g of zinc with 200 ml of 20% hydrochloric acid solution.

This chemical reaction converts the zinc metal into a zinc chloride salt.

Zn + 2HCl = ZnCl2 + H2;

Let’s find the chemical amount of hydrogen chloride. For this purpose, we divide its weight by the mass of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 200 x 1.098 x 0.2 / 36.5 = 1.203 mol;

Let’s calculate the molar amount of metallic zinc. To do this, divide its weight by the mass of 1 mole of metal.

N Zn = 30/65 = 0.46 mol;

With this amount of zinc, 0.46 x 2 = 0.92 mol of acid reacts. In this case, 0.46 mol of hydrogen and 0.46 mol of zinc chloride will be obtained. Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.46 x 22.4 = 10.304 liters;