Calculate the amount of hydrogen required to reduce iron from 40 g of iron oxide (3 valence).

univerkov | May 31, 2021 | education

Given:
m (Fe2O3) = 40 g

To find:
V (H2) -?

1) 3H2 + Fe2O3 => 2Fe + 3H2O;
2) n (Fe2O3) = m / M = 40/160 = 0.25 mol;
3) n (H2) = n (Fe2O3) * 3 = 0.25 * 3 = 0.75 mol;
4) V (H2) = n * Vm = 0.75 * 22.4 = 16.8 liters.

Answer: The volume of H2 is 16.8 liters.

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