Calculate the amount of hydrogen that can be released when 1.2 g of magnesium reacts with 10 g of H2SO4.

Given:
m (Mg) = 1.2 g.
m (H2SO4) = 10 g.
interaction of Mg with H2SO4;
Find: V (H2) -?
Decision:
1) Let’s write the reaction equation:
2 Mg + H2SO4 = Mg2SO4 + H2;
From the reaction – 1 mol of H2 is consumed per 2 mol of Mg and 1 mol of H2SO4;
3) Find v (Mg), v (Mg) = 1.2 g / 24 g / mol = 0.05 mol (for v (Mg) = 2 mol from the reaction, v (Mg) = 0.1 mol);
4) Find v (H2SO4), v (H2SO4) = 10 g / 98 g / mol = 1.02 mol;
5) Since there is a lack of Mg, we solve the problem on it:
v (Mg) = v (H2) = 0.1 mol;
6) V (H2) = 0.1 mol * 22.4 L / mol = 2.24 L.