Calculate the amount of hydrogen that will be released by the action of excess sulfuric acid on 11.2 g of iron.

Given:
m (Fe) = 11.2 g

Find:
V (H2) -?

1) Write the equation of a chemical reaction:
H2SO4 + Fe => FeSO4 + H2 ↑;
2) Determine the molar mass of Fe:
M (Fe) = Ar (Fe) = 56 g / mol;
3) Calculate the amount of the substance Fe:
n (Fe) = m (Fe) / M (Fe) = 11.2 / 56 = 0.2 mol;
4) Determine the amount of substance H2 (taking into account the coefficients in the reaction equation):
n (H2) = n (Fe) = 0.2 mol;
5) Calculate the volume of H2 (under normal conditions):
V (H2) = n (H2) * Vm = 0.2 * 22.4 = 4.48 liters.

Answer: The volume of H2 is 4.48 liters.