Calculate the amount of hydrogen that will be released when 48 grams of magnesium reacts with sulfuric acid.

Metallic magnesium dissolves in sulfuric acid solution. The chemical reaction proceeds according to the following equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Let’s calculate the chemical amount of a substance of metallic magnesium.

To do this, divide its weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 48/24 = 2 mol;

The same amount of hydrogen gas will be produced.

Let’s determine the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 2 x 22.4 = 44.8 liters;