Calculate the amount of magnesium oxide substance that will result from the combustion of 6 g of magnesium.

Decision:
1. Let’s compose the reaction equation:
2Mg + O2 = 2MgO – reaction of magnesium combustion in oxygen, magnesium oxide is obtained;
2. Let’s make calculations: M (Mg) = 24.3 g / mol; M (MgO) = 24.3 + 16 = 40.3 g / mol;
Let us determine the number of moles of magnesium, if the mass is known: m (Mg) = 6 g;
Y (Mg) = m (Mg) / M (Mg); Y (Mg) = 6 / 24.3 = 0.25 mol;
1. Let’s make a proportion based on the data of the reaction equation:
0.25 mol (Mg) – X mol (MgO)
-2 mol -2 mol hence, X mol (MgO) = 0.25 * 2/2 = 0.25 mol;
3. Calculate the mass of magnesium oxide by the formula: Y (MgO) = m (MgO) / M (MgO);
Y (MgO) = 0.25 * 40.3 = 10 g.
Answer: The reaction product obtained is magnesium oxide weighing 10 g.