Calculate the amount of moles of iron sulfate (2) that can be obtained by dissolving 84 g of iron in sulfuric acid.

Let’s implement the solution:
1. By the condition of the problem, we write down the equation:
m = 84 g. X mol -?
Fe + H2SO4 = FeSO4 + H2 – redox (ORR), obtained ferrous sulfate, hydrogen;
2. Calculations by formulas:
M (Fe) = 55.8 g / mol.
3. Determine the amount of the original substance, if the mass is known:
Y (Fe) = m / M = 84 / 55.8 = 1.5 mol;
Y (FeSO4) = 1.5 mol since the amount of these substances according to the equation is 1 mol.
Answer: iron sulfate formed in the amount of 1.5 mol.



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