Calculate the amount of nitrogen required to react with 80g of calcium.

1.write the reaction of obtaining calcium nitride:

N2 + 3Ca = Ca3N2;

2.n (Ca) = m (Ca): M (Ca) = 80: 40 = 2 mol;

3.from the equation it can be seen that nitrogen is required three times less than calcium, we will find its chemical amount:

n (N2) = n (Ca): 3 = 2: 3 = 0.67 mol;

4. find the volume according to the equation for gases under normal conditions:

V (N2) = n (N2) * Vm;

V (N2) = 0.67 * 22.4 = 15 dm3.

Answer: 15 dm3.



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