Calculate the amount of oxygen in the combustion of copper with an amount of 2 mol according

Calculate the amount of oxygen in the combustion of copper with an amount of 2 mol according to the scheme Cu + O2 = CuO.

Metallic copper reacts with oxygen to form oxide. The reaction is described by the following chemical equation:

Cu + ½ O2 = CuO ↑;

N Cu = 2 mol;

To oxidize such an amount of copper, it is necessary to take 2 times less oxygen.

Let’s calculate the weight and volume of oxygen.

To find the weight, we multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 2/2 x 32 = 32 grams;