Calculate the amount of oxygen required for complete combustion of 158g propene.

1. We make a chemical equation, not forgetting to put down the coefficients:

C3H8 + 5O2 = 3CO2 + 4H2O.

2. Find the amount of substance C3H8:

n (C3H8) = 158/44 = 3.6 mol.

3. Find the amount of substance O2:

n (O2) = 5n * n (C3H8) = 18 mol.

4. Find the volume of O2:

V (O2) = 18 * 22.4 = 402hp.

Answer: V (O2) = 402l.



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