Calculate the amount of oxygen required for the complete oxidation of metallic copper, if 2.4 mol of copper oxide were formed.

So, let’s write the reaction equation:
2 Cu + O2 = 2 CuO
Let’s compose the proportion (by the amount of substance):
Theoretically, n oxygen = 1 mol, n copper oxide = 2 mol.
Practically n oxygen = x, n copper oxide = 2.4 mol.
1 / x = 2 / 2.4
x = 1.2
Answer: 1.2 mol.



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