# Calculate the amount of oxygen required for the complete oxidation of metallic copper if 2.4 mol

**Calculate the amount of oxygen required for the complete oxidation of metallic copper if 2.4 mol of copper oxide were formed.**

Copper reacts with oxygen to form oxide. The reaction is described by the following chemical reaction equation:

Cu + ½ O2 = CuO ↑;

N CuO = 2.4 mol;

To obtain such an amount of copper oxide, it is necessary to take 2 times less oxygen, which will be 2.4 / 2 = 1.2 mol.

Determine the weight and volume of oxygen.

To find the weight, we multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 2.4 / 2 x 32 = 38.4 grams;

To find the volume of oxygen, we multiply the amount of the substance by the volume of 1 mole of gas (which is 22.4 liters).

m O2 = 2.4 / 2 x 22.4 = 26.88 liters;