Calculate the amount of oxygen required for the complete oxidation of metallic copper if 2.4 mol

Calculate the amount of oxygen required for the complete oxidation of metallic copper if 2.4 mol of copper oxide were formed.

Copper reacts with oxygen to form oxide. The reaction is described by the following chemical reaction equation:

Cu + ½ O2 = CuO ↑;

N CuO = 2.4 mol;

To obtain such an amount of copper oxide, it is necessary to take 2 times less oxygen, which will be 2.4 / 2 = 1.2 mol.

Determine the weight and volume of oxygen.

To find the weight, we multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 2.4 / 2 x 32 = 38.4 grams;

To find the volume of oxygen, we multiply the amount of the substance by the volume of 1 mole of gas (which is 22.4 liters).

m O2 = 2.4 / 2 x 22.4 = 26.88 liters;