Calculate the amount of oxygen required for the complete oxidation of sulfur, if 6.4 g of sulfur (IV) oxide was formed

S + O2 = SO2.

Let us write out the data necessary for solving the problem: Mr (O2) = 32 g, Mr (SO2) = 64 g.

The reaction shows that from 1 mole of oxygen, 1 mole of sulfur oxide is formed, therefore, from 32 g of oxygen, 64 g of oxide is formed. Let’s make the proportion:

32 g – 64 g

x g – 6.4 g.

Hence, we determine that x = 3.2 g is the mass of oxygen required to determine its amount of substance by the formula:

n = m / Mr = 3.2 / 32 = 0.1 mol.