Calculate the amount of oxygen required to burn 120 g of coal.

1. Let’s compose the equation of the chemical reaction:

C + O2 = CO2.

2. Let’s find the chemical amount of burnt coal:

n (C) = m (C) / M (C) = 120 g / 12 g / mol = 10 mol.

3. Using the reaction equation, we find the chemical amount of oxygen, and as a result its volume (Vm – molar volume, constant equal to 22.4 l / mol):

n (O2) = n (C) = 10 mol.

V (O2) = n (O2) * Vm = 10 mol * 22.4 L / mol = 224 L.

Answer: V (O2) = 224 l.



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