Calculate the amount of oxygen required to burn 28g of iron in a fire.

univerkov | September 10, 2021 | education

Given:
m (Fe) = 28 g

Find:
V (O2) -?

Solution:
1) 3Fe + 2O2 => Fe3O4;
2) n (Fe) = m (Fe) / M (Fe) = 28/56 = 0.5 mol;
3) n (O2) = n (Fe) * 2/3 = 0.5 * 2/3 = 0.33 mol;
4) V (O2) = n (O2) * Vm = 0.33 * 22.4 = 7.4 liters.

Answer: The O2 volume is 7.4 liters.

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