Calculate the amount of oxygen required to burn 62 grams of phosphorus.
February 8, 2021 | education
| The oxidation reaction of phosphorus with oxygen is described by the following chemical reaction equation:
2P + 5/2 O2 = P2O5;
2.5 moles of oxygen are reacted with 2 moles of phosphorus. 1 mole of its oxide is synthesized.
Let’s calculate the available chemical amount of phosphorus.
M P = 31 grams / mol;
N P = 62/31 = 2 mol;
This reaction will require 2 x 2.5 / 2 = 2.5 moles of oxygen.
Let’s calculate the volume of oxygen. To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V O2 = 2.5 x 22.4 = 56 liters;
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