Calculate the amount of oxygen required to completely oxidize 90g of glucose. How much CO2 will be released?

The oxidation reaction of glucose with oxygen is described by the following chemical reaction equation:
C6H12O6 + 6O2 = 6CO2 + 6H2O;
6 moles of oxygen interact with 1 mole of glucose. This synthesizes 6 mol of carbon monoxide.
Let’s calculate the available chemical amount of glucose.
M С6Н12О6 = 12 x 6 + 12 + 16 x 6 = 180 grams / mol;
N C6H12O6 = 90/180 = 0.5 mol;
This reaction requires 0.5 x 6 = 3 moles of oxygen.
Let’s calculate its volume by multiplying the amount of the substance by the volume of 1 mole of the gaseous substance.
V O2 = 3 x 22.4 = 67.2 liters;