Calculate the amount of phosphorus substance (mol) during the combustion of which 56.8 g

Calculate the amount of phosphorus substance (mol) during the combustion of which 56.8 g of phosphorus was mowed 5.

The oxidation reaction of phosphorus to oxygen is described by the following chemical reaction equation.

4P + 5O2 = 2P2O5;

The phosphorus oxide molecule has two phosphorus atoms. Therefore, to obtain one mole of phosphorus oxide, two moles of phosphorus are required.

Let’s find the amount of the substance contained in 56.8 grams of phosphorus oxide.

Its molar mass is.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

The amount of the substance will be.

N P2 O5 = 56.8 / 142 = 0.4 mol;

Let’s find the amount of phosphorus substance.

The amount of the substance will be.

N P = N P2 O5 x 2 = 0.4 x 2 = 0.8 mol;