Calculate the amount of phosphorus substance required for the reaction with oxygen in the amount of 56 mol.

Calculate the amount of phosphorus substance required for the reaction with oxygen in the amount of 56 mol. Chemical reaction equation: 4P + 5O2 = 2P2O5.

4 P + O2 = 2 P2O5.
According to the reaction equation, there is 1 mole of oxygen for 4 mol of phosphorus. Substances are in quantitative ratios of 4: 1. Therefore, the amount of phosphorus substance will be 4 times greater than the amount of oxygen substance.
4 mol Р – 1 mol О2,
x mol Р – 56 mol О2,
x mol P = (56 mol × 4 mol): 1 = 224 mol.
Answer: 224 mol.