Calculate the amount of phosphorus (V) oxide substance obtained by combustion of 24.8 g. phosphorus.

The oxidation reaction of phosphorus with oxygen is described by the following chemical reaction equation:

2P + 5/2 O2 = P2O5;

2.5 moles of oxygen are reacted with 2 moles of phosphorus. 1 mol of its oxide is synthesized.

Let’s calculate the available chemical amount of phosphorus.

M P = 31 grams / mol;

N P = 24.8 / 31 = 0.8 mol;

In this case, 0.8 / 2 = 0.4 mol of phosphorus oxide will be synthesized.

Let’s calculate its weight.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

m P2O5 = 142 x 0.4 = 56.8 grams;