Calculate the amount of silver chloride in which will be released during the interaction
| May 15, 2021 | education
Calculate the amount of silver chloride in which will be released during the interaction of silver nitrate, weighing 17 grams, with calcium chloride.
CaCl2 + 2AgNO3 = Ca (NO3) 2 + 2AgCl (sediment)
Let’s calculate the amount of silver nitrate substance:
n (AgNO3) = m (AgNO3) / M (AgNO3) = 17/170 = 0.1 mol;
Based on the stoichiometric reaction coefficients:
n (AgNO3) = n (AgCl) = 0.1 mol.
Answer: n (AgNO3) = 0.1 mol.
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