Calculate the amount of slaked lime that can be obtained from 2 tons of limestone

Calculate the amount of slaked lime that can be obtained from 2 tons of limestone containing 25% impurities.

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

The decomposition of 1 mol of limestone synthesizes 1 mol of calcium oxide and 1 mol of carbon monoxide.

Find the molar amount of calcium carbonate. For this purpose, we divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 2,000,000 x 0.75 / 100 = 15,000 mol;

Let us determine the weight of 15,000 mol of calcium hydroxide.

To do this, we multiply the amount of the substance by its molar weight.

M Ca (OH) 2 = 40 + (16 + 1) x 2 = 74 grams / mol;

m Ca (OH) 2 = 15,000 x 74 = 1,110,000 grams = 1.11 tons;