Calculate the amount of sodium substance that has reacted with water if 112 liters of H2 are evolved.

First, let’s write the formula for the reaction of sodium and water.
Na + H2O = NaOH + H2
Let’s arrange the coefficients.
2Na + 2H2O = 2NaOH + H2
Based on this formula, we know that the amount of sodium substance entered 2 times the amount of hydrogen substance: n (H2) = 1/2 * n (Na)
Knowing the volume of the released gas, we will find its amount of matter.
n (H2) = V / Vm = 112 L / 22.4 L / mol = 5 mol
Knowing n (H2), we find n (Na) using the formula derived earlier.
n (H2) = 1/2 * n (Na) = 5 mol
n (Na) = 5 mol * 2 = 10 mol
Answer: 10 mol