Calculate the amount of substance and the mass of alkali that were obtained by the interaction

Calculate the amount of substance and the mass of alkali that were obtained by the interaction of 620 g of sodium oxide with water.

When sodium oxide is mixed with water, its base is formed:

Na2O + H2O = 2NaOH;

The oxide has two sodium atoms, and the hydroxide has only one atom.

Therefore, from one mole of sodium oxide, two moles of a base are formed.

Find the number of moles of a substance contained in 620 grams of sodium oxide.

Its molar mass is:

M Na2O = 23 x 2 + 16 = 62 grams / mol;

The amount of the substance is determined by dividing its mass by the molar mass:

N Na2O = 620/62 = 10 mol;

First, we find the amount of the substance, and then we find the mass of the alkali.

The amount of the alkali substance will be twice as much as the amount of the oxide substance.

N NaOH = 2 x N Na2O = 2 x 10 = 20 mol;

M NaOH = 23 + 16 + 1 = 40 grams / mol;

To find the mass of alkali, you need to multiply the amount of the substance by its molar mass:

m NaOH = N NaOH x M NaOH = 20 x 40 = 800 grams;