Calculate the amount of substance and the mass of alkali, which was obtained by the interaction of 62 g of sodium oxide with water.

The reaction of sodium oxide with water is described by the following chemical reaction equation:
Na2O + H2O = 2NaOH;
From one mole of sodium oxide, two moles of alkali are formed.
Let’s determine the amount of substance in 62 grams of sodium oxide.
M Na2O = 23 x 2 + 16 = 62 grams / mol;
N Na2O = 62/62 = 1.0 mol;
Let’s find the amount of substance and mass of alkali
N NaOH = 2 N Na2O = 2 x 1.0 = 2 mol;
M NaOH = 23 + 16 + 1 = 40 grams / mol;
m NaOH = N NaOH x M NaOH = 2 x 40 = 80 grams;