Calculate the amount of substance and the mass of copper hydroxide (ll), which can neutralize 12.6 g of nitric acid.
| April 26, 2021 | education
Copper hydroxide neutralization reaction.
Cu (OH) 2 + 2HNO3 = Cu (NO3) 2 + 2H2O.
Determine the number of moles of nitric acid.
n (HNO3) = m / Mr = 12.6 / 63 = 0.2 mol.
It follows from the reaction equation that the amount of moles of acid is twice the amount of hydroxide.
n (Cu (OH) 2) = n (HNO3) / 2 = 0.2 / 2 = 0.1 mol.
So the mass of copper hydroxide is.
m (Cu (OH) 2) = n • Mr = 0.1 • 98 = 9.8 g.
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