Calculate the amount of substance and the mass of magnesium carbonate formed

Calculate the amount of substance and the mass of magnesium carbonate formed by the interaction of magnesium hydroxide with 10 g of carbon monoxide

Given:
m (CO2) = 10 g

Find:
n (MgCO3) -?
m (MgCO3) -?

Solution:
1) Mg (OH) 2 + CO2 => MgCO3 + H2O;
2) n (CO2) = m (CO2) / M (CO2) = 10/44 = 0.2 mol;
3) n (MgCO3) = n (CO2) = 0.2 mol;
4) m (MgCO3) = n (MgCO3) * M (MgCO3) = 0.2 * 84 = 16.8 g.

Answer: The amount of MgCO3 substance is 0.2 mol; weight – 16.8 g.