Calculate the amount of substance and the mass of magnesium hydroxide reacted with 0.1

univerkov | June 23, 2021 | education

Calculate the amount of substance and the mass of magnesium hydroxide reacted with 0.1 mol of carbon monoxide (IV).

Given:
n (CO2) = 0.1 mol

To find:
n (Mg (OH) 2) -?
m (Mg (OH) 2) -?

Decision:
1) Mg (OH) 2 + CO2 => MgCO3 + H2O;
2) n (Mg (OH) 2) = n (CO2) = 0.1 mol;
3) m (Mg (OH) 2) = n * M = 0.1 * 58 = 5.8 g.

Answer: The mass of Mg (OH) 2 is 5.8 g.

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