Calculate the amount of substance and the mass of oxygen formed during decomposition: 2 mol of chromium oxide

Calculate the amount of substance and the mass of oxygen formed during decomposition: 2 mol of chromium oxide (6) reaction equation: 4CrO3 = 2Cr2O3 + 3O2

Let’s implement the solution:
1. We compose the equation according to the condition of the problem:
Y = 2 mol Y -? m -?
4CrO3 = 2Cr2O3 + 3O2 – decomposition, obtained oxygen, chromium oxide (3);
2. Calculations:
M (O2) = 32 g / mol.
M (CrO3) = 99.9 g / mol.
3. Proportion:
2 mol (CrO3) – X mol (О2);
– 4 mol – 3 mol from here, X mol (O2) = 2 * 3/4 = 1.5 mol.
4. Find the mass of the product:
m (O2) = Y * M = 1.5 * 32 = 48 g.
Answer: oxygen was obtained with a mass of 48 g, an amount of 1.5 mol.