Calculate the amount of substance and the mass of sodium required for the reaction with chlorine in a volume of 4.48 liters.

1. Let’s write the equation of the reaction of sodium with chlorine:

2Na + Cl2 = 2NaCl;

2.Calculate the chemical amount of chlorine:

n (Cl2) = V (Cl2): Vm = 4.48: 22.4 = 0.2 mol;

3. Determine the amount of sodium entering into the reaction:

n (Na) = n (Cl2) * 2 = 0.2 * 2 = 0.4 mol;

4.calculate the mass of sodium:

m (Na) = n (Na) * M (Na) = 0.4 * 23 = 9.2 g.

Answer: 0.4 mol; 9.2 g