# Calculate the amount of substance and the mass of the formed aluminum oxide Al2O3, if 3 mol of aluminum has entered

Calculate the amount of substance and the mass of the formed aluminum oxide Al2O3, if 3 mol of aluminum has entered into a reaction with oxygen. Reaction scheme: Al + O2 = Al2O3

The reaction of aluminum with oxygen proceeds according to the following chemical formula:

4Al + 3O2 = 2Al2O3;

From two moles of aluminum, one mole of aluminum oxide is formed.

The amount of aluminum oxide substance will be:

N Al2O3 = N Al / 2 = 3/2 = 1.5 mol;

Find the mass of this amount of aluminum oxide:

M Al2O3 = 27 x 2 + 16 x 3 = 102 grams / mol;

m Al2O3 = 1.5 x 102 = 153 grams;

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