Calculate the amount of substance and the mass of the resulting copper if Cu (II) oxide with a mass of 64 g reacts with hydrogen.

Given:
m (CuO) = 64 g
To find:
n (Cu)
m (Cu)
Decision:
CuO + H2 = Cu + H2O
n (CuO) = m / M = 64 g / 80 g / mol = 0.8 mol
n (CuO): n (Cu) = 1: 1
n (Cu) = 0.8 mol
m (Cu) = n * M = 0.8 mol * 64 g / mol = 51.2 g
Answer: 0.8 mol; 51.2 g



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