Calculate the amount of substance contained in 56L of ammonia NH3. How many molecules are there

Calculate the amount of substance contained in 56L of ammonia NH3. How many molecules are there in a given ammonia sample? How many hydrogen atoms are there in a given ammonia sample?

Given:
V (NH3) = 56 l.
To find:
n (NH3) -?
N (NH3) -?
N (H) -?
Decision:
n (NH3) = V / Vm = 56 L: 22.4 L / mol = 5 mol.
N (NH3) = Na × n = 6 × 10 ^ 23 × 5 mol = 3 × 10 ^ 24 molecules.
N (H) = N (NH3) × 3 = 3 × 10 ^ 24 × 3 = 9 × 10 ^ 24 atoms.
Answer: N (NH3) = 3 × 10 ^ 24 molecules; N (H) = 9 × 10 ^ 24 atoms; n (NH3) = 5 mol.