Calculate the amount of substance, mass and number of molecules for 56 liters of fluorine gas.

V (F) = 56 HP
Let’s determine the mass, the amount of the substance and the number of molecules. We write down the solution.
We find the amount of substance.
n = V / Vm.
n = 56 L / 22.4 L / mol = 2.5 mol.
Next, we find the number of molecules, for this we use the following formula.
N = n * Na.
Where N is the number of molecules.
n is the amount of substance.
Na is Avogardo’s number, constant 6.02 * 10’23.
N = 2.5 * 6.02 * 10’23 = 15.05 * 10’23 molecules.
Next, we find the mass of fluorine.
n = m / M.
M (F) = 19 g / mol.
m = n * M = 2.5 * 19 = 47.5 g.
Answer: m = 47.5 g; n = 2.5 mol; N = 15.05 * 10’23 molecules.