Calculate the amount of substance, mass and number of water molecules formed

Calculate the amount of substance, mass and number of water molecules formed by the interaction of 37 g of calcium hydroxide with nitric acid.

Calcium hydroxide with nitric acid enters into a neutralization reaction with the formation of water and calcium nitrate salt. Let’s write the equation of this reaction:

Ca (OH) 2 + 2 HNO3 = Ca (NO3) 2 + 2 H2O

To solve the problem according to the reaction equation, we calculate the mass of the formed water, and only then from this value we calculate the amount of substance and the number of molecules.

To find the amount of a substance, we will compose the proportion:

37 g of calcium hydroxide corresponds to X mol of water as

74 g / mol of calcium hydroxide corresponds to 2 mol of water

X = (37 * 2) / 74 = 1 mole of water formed

The molar mass of water is 18 g / mol. So the mass of the resulting water = 1 * 18 = 18 g.

According to Avogadro’s law, the number of molecules in 1 mole of any substance under normal conditions. equals 6.02 * 10 ^ 23 units. So the number of water molecules is 6.02 * 10 ^ 23.

Answer: 18 years; 1 mole; 6.02 * 10 ^ 23 molecules