Calculate the amount of substance (mol) potassium required for the reaction with 2.24 liters of chlorine.

To solve the problem, we write down the equation, select the coefficients:
2K + Cl2 = 2KCl – the reaction of the compound, potassium chloride is released;
M (K) = 39.1 g / mol;
M (Cl2) = 71 g / mol.
Determine the amount of chlorine mol:
1 mol of gas at n, y – 22.4 liters.
X mol (Cl2) – 2.24 L. hence, X mol (Cl2) = 1 * 22.4 / 2.24 = 0.1 mol.
We make the proportion according to the equation:
X Mol (K) – 0.1 mol (Cl2);
-2 mol -1 mol hence, X mol (K) = 2 * 0.1 / 1 = 0.2 mol.
Answer: to carry out the reaction, you need potassium in the amount of 0.2 mol.



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