Calculate the amount of substances contained in 150 g CaSO4 and 7 g HNO3.

univerkov | November 21, 2020 | education

1) Given: m (CaSO4) = 150 g
Find: n (CaSO4)
Decision:
m (CaSO4) = nM => n (CaSO4) = m / M
M (CaSO4) = 40 + 32 + 16 * 4 = 136 g / mol
n (CaSO4) = 150g / 136 g / mol = 1.103 mol
Answer: 1.103 mol

2. Given: m (HNO3) = 7g
Find: n (HNO3)
Decision:
m (HNO3) = nM => n (HNO3) = m / M
M (HNO3) = 1 + 14 + 16 * 3 = 63 g / mol
n (HNO3) = 7g / 63 g / mol = 0.111 mol
Answer: 0.111

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