Calculate the amount of the substance and the mass of water that is formed during the neutralization of NaOH

Calculate the amount of the substance and the mass of water that is formed during the neutralization of NaOH with a mass of 4 g: a) hydrochloric acid b) sulfuric acid c) phosphoric acid Indicate the type of reaction

Given:
m (NaOH) = 4 g

Find:
n (H2O) -?
m (H2O) -?

1) n (NaOH) = m / M = 4/40 = 0.1 mol;
a) HCl;
2) NaOH + HCl => NaCl + H2O;
3) n (H2O) = n (NaOH) = 0.1 mol;
4) m (H2O) = n * M = 0.1 * 18 = 1.8 g;
b) H2SO4;
5) 2NaOH + H2SO4 => Na2SO4 + 2H2O;
6) n (H2O) = n (NaOH) = 0.1 mol;
7) m (H2O) = n * M = 0.1 * 18 = 1.8 g;
c) H3PO4;
8) 3NaOH + H3PO4 => Na3PO4 + 3H2O;
9) n (H2O) = n (NaOH) = 0.1 mol;
10) m (H2O) = n * M = 0.1 * 18 = 1.8 g.

Answer: The amount of substance H2O is 0.1 mol; weight – 1.8 g.