Calculate the amount of the substance of the formed copper, if copper (II) oxide with a mass of 64 g enters

Calculate the amount of the substance of the formed copper, if copper (II) oxide with a mass of 64 g enters into a reaction with hydrogen (CuO + H2 = Cu + H2O)

To solve this problem, we write down given: m (CuO) = 64 g

Find: the amount of copper substance formed as a result of the reaction.

Decision:

To solve this problem, we write down the reaction equation:

CuO + H2 = Cu + H2O

Let’s calculate the molar mass of copper (II) oxide.

M (CuO) = 64 + 16 = 80 g / mol

We write 64 g over copper (II) oxide, and with copper (II) oxide, its molar mass is 80 g.

Above the copper, which was formed as a result of the reaction, we write x mol, and under the copper – 1 mol.

Let’s compose and solve the proportion:

x = 64 g * 1 mol / 80 g = 0.8 mol

Answer: 0.8 mol