Calculate the amount of the substance of the formed copper if copper (II) oxide with a mass of 64 g reacts with hydrogen.

Given:

m (CuO) = 64g

To find :

n (Cu) = x mol

Decision.

1. Let’s write the reaction equation: CuO + H2 = Cu + H2O

According to the reaction equation, from 1 mol of CuO, 1 mol of Cu is reduced by hydrogen (the coefficients in front of the formulas are the amount of substance in moles).

2. Let’s find how many mol of CuO entered into the reaction.

n (CuO) = m (CuO) / M (CuO), where M (CuO) = 64 + 16 = 80 g / mol, hence n (CuO) = 64 g / 80 g / mol = 0.8 mol.

3. Since, according to the reaction equation, from 1 mol of CuO 1 mol of Cu is formed, then from 8 mol of CuO – 0.8 mol of Cu.