Calculate the amount of the substance of the formed copper if copper (II) oxide with a mass of 64 g reacts with hydrogen

Copper oxide is reduced with hydrogen gas. This synthesizes metallic copper and water. The reaction is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

Cupric oxide reacts with hydrogen in equal (equivalent) molar amounts. In this case, equal (equivalent) amounts of metallic copper and water are synthesized.

Let’s determine the chemical amount of copper oxide.

For this purpose, we divide the weight of the oxide by the weight of 1 mole of oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 64/80 = 0.8 mol;

Thus, 0.8 mol of copper oxide can be reduced and 0.8 mol of copper can be obtained.

Its weight will be:

M Cu = 64 grams / mol;

m Cu = 64 x 0.8 = 51.2 grams;