Calculate the amount of the substance of the formed salt in the reaction of 102 g of aluminum oxide with sulfuric acid.

To solve the problem, let’s compose the equation:
m = 102 g. Y mol -?
1. Al2O3 + 3H2SO4 = Al2 (SO4) 3 + 3H2O – ion exchange, formed aluminum sulfate, water;
2. Calculations:
M (Al2O3) = 101.8 g / mol;
M Al2 (SO4) 3 = 341.8 g / mol.
4. Determine Y of the initial substance, if the mass is known:
Y (Al2O3) = m / M = 102/1 – 1.8 = 1 mol.
Y Al2 (SO4) 3 = 1 mol since the amount of substances is equal to 1 mol according to the equation.
Answer: 1 mol of aluminum sulfate salt was formed.